Use a transformation to solve the equation.    f ∙ 8 = 40 a f=5 b f=32 c f=48 df=320

Using Taylor expansion, show that
f0
(x0) = f(x0 + h) − f(x0)
h − h
2
f00(ξ),
for some ξ lying in between x0 and x0 + h.
Solution: We expand the function f in a first order Taylor polynomial around x0:
f(x) = f(x0)+(x − x0)f0
(x0)+(x − x0)
2 f00(ξ)
2 ,
where ξ is between x and x0. Let x = x0 + h:
f(x0 + h) = f(x0) + hf0
(x0) + h2
2 f00(ξ).
Solving for f0
(x0), we obtain:
f0
(x0) = f(x0 + h) − f(x0)
h − h
2
f00(ξ)

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote