Mathematics, 09.07.2019 11:00 yay47

Asurveyor took the following measurements from two irregularly shaped pieces of land. some of the lengths and angle measures are missing. find all missing lengths and angle measures. round lengths to the nearest tenth and angle measures to the nearest minute

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Answer from: Jc8777

Part A:

To find angle D, we make use of the rule of Sines because we know the measure of the side opposite angle D and we also know the meansure another angle of the triangle with the measure of the side opposite the angle.

Thus, we find angle D as follows:

$\frac{62}{\sin{D}} = \frac{51}{\sin{53^o}} \\ \\ \Rightarrow \sin{D}= \frac{62\sin{53^o}}{51}} \\ \\ = \frac{49.5154}{51} =0.9709 \\ \\ \Rightarrow D=\sin^{-1}{0.9709} \\ \\ =76.14^o=76^o8'$

Therefore, angle D is 76°8'

Part B:

To find angle E, recall that the sum of the angles in a triangle is 180°.

Thus, 53° + 76°8' + E = 180°

E = 180° - 53° - 76°8' = 50°52'

Therefore, angle E is 50°52'

Part C:

To find the measure of side e, we apply the cosine rule as follows:

$e^2=51^2+62^2-2(51)(62)\cos{50^o52'} \\ \\ =2,601+3,844-2,098.85=3,991.25 \\ \\ \Rightarrow e=\sqrt{3,991.25}=63.18$

Therefore, the measure of side e is 63.2

Part D

To find angle G, we make use of the rule of Sines because we know the measure of the side opposite angle G and we also know the measure another angle of the triangle with the measure of the side opposite the angle.

Thus, we find angle G as follows:

$\frac{80}{\sin{G}} = \frac{62}{\sin{49^o}} \\ \\ \Rightarrow \sin{G}= \frac{80\sin{49^o}}{62} \\ \\ = \frac{60.3768}{62} =0.9738 \\ \\ \Rightarrow G =\sin^{-1}{0.9738}=76.86^o=76^o52'$

Therefore, angle G is 76°52'

Part E:

To find angle H, recall that the sum of the angles in a triangle is 180°.

Thus, 49° + 76°52' + H = 180°

H = 180° - 49° - 76°52' = 54°14'

Therefore, angle H is 54°14'

Part F:

To find the measure of side a, we apply the cosine rule as follows:

$a^2=80^2+62^2-2(80)(62)\cos{54^o14'} \\ \\ =6,400+3,844-5,798.10=4,445.90 \\ \\ \Rightarrow a=\sqrt{4,445.90}=66.68$

Therefore, the measure of side a is 66.7

Part G:

To find angle A, we make use of the rule of Sines because we know the measure of the side opposite angle A and we also know the measure another angle of the triangle with the measure of the side opposite the angle.

Thus, we find angle A as follows:

$\frac{66.7}{\sin{A}}
 = \frac{30}{\sin{25^o54'}} \\ \\ \Rightarrow \sin{A}= 
\frac{66.7\sin{25^o54'}}{30} \\ \\ = \frac{29.1347}{30} =0.9712 \\ \\ 
\Rightarrow A =\sin^{-1}{0.9712}=76.21^o=76^o12'$

Therefore, angle A is 76°12'

Part H:

To find angle B, recall that the sum of the angles in a triangle is 180°.

Thus, 25°54' + 76°12' + B = 180°

B = 180° - 25°54' - 76°12' = 77°53'

Therefore, angle B is 77°53'

Part I:

To find the measure of side b, we make use of the rule of sines

Thus, we find side b as follows:

$\frac{b}{\sin{77^o53'}} = \frac{30}{\sin{25^o54'}} \\ \\ 
\Rightarrow b= \frac{30\sin{77^o53'}}{\sin{25^o54'}} \\ \\ = 
\frac{29.3317}{0.4368} =67.15$

Therefore, the measure of side b is 67.2

Answer from: Quest

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

(x^4) ^ ¼ = 81 ^ ¼

81 = 3^4 so (3 ^ 4) ^ ¼ = 3 ^ 1 = 3

by hand: (3 ^ 4) ^ ¼ = 3 ^ (4 x ¼) = 3 ^ 1 = 3 (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

How to find a number whose 4th power is 81 quickly?

Answer from: Quest

Yeah me i need badly

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Asurveyor took the following measurements from two irregularly shaped pieces of land. some of the le...