Geraldine is picking a four-digit password by using the digits 0 through 9. she can use each digit only once. how many different passwords are possible?

The number of different possible passwords are possible

Given that each digit can be used once, then:

So, the number of passwords is:

n = 10 * 9 * 8 * 7

Evaluate the products

n = 5040

Hence, there are 5040 different possible passwords

Read more about permutation and combination at:

link

0-9 = 10 numbers

 1st digit can be 1 0f 10

2nd digit can be 1 of 9

3rd digit can be 1 of 8

4th digit can be 1 of 7

10 * 9 *8*7 = 5040 different combinations

the last choice

step-by-step explanation:

table 3 represents a direct variation function. : )