Answers: 1
defined by 
defined by 
, -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular 
, defined by 
, defined by 
, defined by ![\left([x_{12}]\right)=[x_4]](/tpl/images/0072/7295/ae372.png)
, where ![[u_n]](/tpl/images/0072/7295/89c12.png)
denotes the lass of the integer 
in 
.![[a_{12}],[b_{12}]\in Z_{12}](/tpl/images/0072/7295/3f79c.png)
, we have ![f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)](/tpl/images/0072/7295/aa2bd.png)
![f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)](/tpl/images/0072/7295/93157.png)
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