There are four families attending a concert together. each family consists of 1 male and 2 females. in how many ways can they be seated in a row of twelve seats i

Each family sits together. They all sit on adjacent 3 seats.  3! x 3! X 3! X 3! And they can be rearranged in 4! Ways. 

Total ways = (3!)^4 x 4!=6^4 x 24=31104 

There are 31104 ways they can be seated in a row of twelve seats

lol we need to see what the question is asking about

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