Two cars leave town going in opposite directions. one car is traveling 55 miles per hour (mph), and the other car is traveling 40 mph. how long will it take before the cars are 285 miles apart?

The distance, d, traveled by a car going at speed, s, in time, t, is
d = st

Car 1 travels distance 1, d1, at s1 = 55 mph, for t1 time.
Car 2 travels distance 2, d2, at s2 = 40 mph, for t2 time.

The two distances add to 285 miles, so
d1 + d2 = 285
The two times are equal, so t1 = t2 = t

d1 = 55t1
d2 = 40t2

d1 = 55t
d2 = 40t

d1 + d2 = 55t + 40t

d = 95t

285 = 95t

95t = 285

t = 3

It will take 3 hours.

Note:
This problem shows you that if two cars are traveling along the same line in opposite directions, the speed at which they are distancing themselves is the sum of the two speeds. We can solve the problem in a simpler way:

55 mph + 40 mph = 95 mph

d = st

285 = 95t

t = 3

3 hours.

Uneed to add them up 27+18+23=68

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.