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Mathematics, 21.06.2019 22:10
Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.
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Mathematics, 21.06.2019 22:20
Which graph has figures that can undergo a similarity transformation to justify that they are similar? (obviously not the third one)
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Mathematics, 21.06.2019 22:30
Adistribution has the five-number summary shown below. what is the third quartile, q3, of this distribution? 22, 34, 41, 55, 62
Answers: 2
Round off 3.55 to one significant figure...
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