Which does not describe the same situation?

y = 3+6x

Step-by-step explanation:

Let us substitute x = 0, then we get

y = 3

This is not the case as the graph clearly shows that when x = 3, then y = 2

y = 2+6x

when x = 0 then y = 2 which valid from the graph

Now put x values from the table into the equation

y = 2+6×-1

⇒y = -4

x = 0 already solved

x = 2

y = 2+6×2

⇒y = 14

All the values fit in the equation. So, the bottom two options are valid.

Hence, the first equation is not valid.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it