What is the range of the function y = x2?

The range of this function is y is equal to all real numbers such that y 0.

In order to find the range of y, we must look for the minimum or maximum value. In a quadratic, this number exists at the vertex. To find the vertex, we use the equation -b/2a, where a is equal to the coefficient of x^2 and b is equal to the coefficient of x. Since there is no x, the coefficient is 0.

x value of vertex = -b/2a

x value of vertex = -0/2(1)

x value of vertex = 0

So then we can look for the minimum y value by plugging in the x value into the equation.

y = x^2

y = x^2

y = 0

Therefore the minimum is 0 and there is no maximum.

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

answer: it is 8

step-by-step explanation:

you know why its 8