Acustomer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels, and nine (9) pennies. the customer buys a pair of shoes for $49.86. based on the combination of bills and coins the customer has, what are the least number of bills and coins the customer can give the cashier in order to buy the shoes for the exact amount and not require any change back?

A combination of 9 bills and 5 coins is the least number of bills and coins.

Step-by-step explanation:

A customer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels, and nine (9) pennies.

1 quarter = $0.25

1 dime = $0.10

1 penny = $0.01

1 nickel = $0.05

The customer buys a pair of shoes for $49.86.

So, we can split this as following:

49 can be split as 40+9

So, bills =$40

bill = $5

bill = $4

Total is $49 made from 9 bills.

For the decimal part, we can split as :

quarters = $0.75

dime = $0.10

penny = $0.01

Total becomes = $0.86 from 5 coins.

Hence, a combination of 9 bills and 5 coins is the least number of bills and coins the customer can give the cashier in order to buy the shoes for the exact amount and not require any change back.

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.