What is the equation for the line of reflection that maps the trapezoid onto itself? x = 0 x = 3 y = 3 y = 0?

The given trapezoid has a line of symmetry that is at the midpoint of the base of the tapezoid.

Given that the base of the trapezoid runs from point (-3, 2) to point (7, 2), the midpoint is given by (-3 + 7) / 2 = 4 / 2 = 2.

Thus, the line of refrection the maps the trapezoid onto itself is x = 2.

59/96 is the ratio hope this not 100% sure though : /