Arectangular fountain display has a perimeter of 400 feet and an area of at least 9100 feet. describe the possible widths of the fountain

Perimeter = 2L + 2W = 400 = 2(L+W) Therefore L + W = 200 Area = L * W = 9100 Where L= Length and W = Width Find Multiples of 9,100 which can sum up to 200. The answer is 130 and 70. Checking. 130 * 70 = 9100 2(130 + 70) = 400 The possible width of the Fountain is 70 feet if the Length is longer or 130 feet if the length is shorter.

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