Find the critical numbers of the function. (enter your answers as a comma-separated list.) f(θ) = 8sec θ + 4tan θ,     0 < θ < 2π

Critical numbers of the functionF(o) = 8 sec θ + 4 tan θ, 0 < θ <2 π.F(o) = 0 for critical numbersF(o) = 8 sec θ tan θ + 4 sec^2 θ = 0        = 4 sec θ [2 tan θ + 4 sec θ] = 0Sec θ = 0 or 2 tan θ + sec θ = 0Sec θ = 0 is no solution.2 tan θ + sec θ = 0 => (2 sin θ / cos θ) + (1 / cos θ) = 0 (2 sin θ + 1 / cos θ) = 0 => 2 sin θ + 1 = 0Sin θ = -1/2Θ = 7π/6 , 11π/6 Therefore, critical number are 7π/6 , 11π/6

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