Aquadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. write the equation in general form.

x² + b²

Explanation:

1) Quadratic equation form, showing the two roots r₁ and r₂:

A (x - r₁)(x - r₂).

2) Coefficient 1 ⇒ A = 1

3) Complex roots ⇔ the roots are conjugate

4) r₁ = -bi ⇒ conjugate = bi = r₂

5) Replace -bi and bi for r₁ and r₂ in the general form:

[x - (-bi) ] [ x - bi] = (x + bi) (x - bi) = x² - (-bi)² = x² + b²

x² + b²

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.