The larger of two numbers is nine more than four times the smaller number the sum of the two numbers is 59 find the two numbers

Smaller number = x
Larger number = 4x + 9
sum of the two numbers is 59
x + (4x + 9) = 59

Solve for x, which is the smaller number
x + (4x + 9) = 59
x + 4x + 9 = 59
5x + 9 = 59
5x = 59-9
5x = 50
5x / 5 = 50 / 5
x = 10

Smaller number = 10
Larger Number: Insert 10 into x
4x + 9
4(10) + 9
40 + 9 = 49

Larger number = 49
Smaller number = 10
Smaller + Larger =  59
10         +  49      =   59

Ithink if im not mistaking b is -3 but im not a 100% sude

What’s your question.