Mathematics, 13.07.2019 10:30 Monicaamm12983

$(1 + 0.12 \div 12) { 12 \times 1 \div 2} - 1 \div 0.12 \div 12 =$

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The answer is:
________________________________________________________
" $\frac{4829}{900}$ "; or, "5 $\frac{329}{900}$ " ;
or, write as: "5.366" .
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Explanation:
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Given: " (1 + 0.12 ÷ 12)12 * 1 ÷ 2− 1 ÷ 0.12 ÷ 12 = ? " ;
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First, start with the "parentheses" ;
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"(1 + 0.12 ÷ 12) = ??

Start with the division: " 0.12 ÷ 12 = 0.01 " .

"(1 + 0.01)" = (1.01) .

We have: "1.01 (12)
Given: " (1.01)12 * 1 ÷ 2 − 1 ÷ 0.12 ÷ 12 = ? " ;

So, 1.01 * 12 = 12 .12 .
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" 12.12 * 1 ÷  2 − 1 ÷ 0.12 ÷ 12 = ? " ;

Note: Using order of operations, treat this problem as:

" [ (12.12 * 1) ÷  2 ] − [ (1 ÷ 0.12) ÷ 12 ] = ? " ;

→ ( 12.12 ÷ 2 ) − (25/3) ÷ 12 ] = ? " ;

→ ( 6.06) − { (25/3) * 1/12) } = ?

→ ( 6.06) − { ( 25* 1) / (3*12) = ?

→ ( 6.06) − { ( 25* 1) / (3*12) = ?

→ ( 6.06) − (25/36) ;

→ 6 $\frac{6}{100}$ − $\frac{25}{36}$   ;

→ 6 $\frac{3}{50}$ − $\frac{25}{36}$   ;

Rewrite " 6 $\frac{3}{50}$ " ; as an improper fraction:

→ " 6 $\frac{3}{50}$ " = "[ (50*6) + 3 ] / 50 = $\frac{303}{50}$ ;
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→ 6 $\frac{3}{50}$ − $\frac{25}{36}$ ;

= $\frac{303}{50}$   − $\frac{25}{36}$ ;

= $\frac{(303*36)-(25*50)}{50*36} = \frac{10,908-1250}{1800}$ ;

= $\frac{9658}{1800}$ ;
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→ Divide EACH SIDE of the "fraction" by "2" ; to simplify:
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→ $\frac{9658/2}{1800/2}$ ;
= $\frac{4829}{900}$ = 5 $\frac{329}{900}$ ; or, write as:

(5 + (329 ÷ 900) = → 5.3655555555555556 .
→ round to: 5.366 .
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[tex](1 + 0.12 \div 12) { 12 \times 1 \div 2} - 1 \div 0.12 \div 12 = [/tex]...

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