Fast and show all work! is the line through points p(-8-10) and q(-5,-12) perpendicular to the line through points r(9,-6) and s(17,-5)? explain.

Well let's find the slope of both coordinates first.

Slope = y2 - y1 / x2 - x1

1) Find the slope of PQ

Slope = -12 - (-10) / -5 - (-8)

Slope = -12 + 10 / -5 + 8

Slope = -2 / 3

Slope = - 2 / 3

The slope is negative two-thirds.

2) Find the slope of RS

Slope = -5 - (-6) / 17 - 9

Slope = -5 + 6 / 8

Slope = 1/8

The slope is one over eight

Solution: Since the slopes are not negative reciprocals of each other, they cannot be perpendicular.

Bc equals mb that should be your answer