The side lengths of triangle abc are written in terms of the variable p, where p ≥ 3.which is correct regarding the angles of the triangle? ma >   mc >   mb  mb >   ma >   mcmc >   ma >   mbmc >   mb >   ma

C) mC > mA > mB is correct regarding the angles of the  triangle ABC.

Step-by-step explanation:

Given: In Δ ABC, the side lengths of triangle ABC are written in terms of the variable p, where p ≥ 3.

AB=4p-1 , AC=p+4 , BC=3p

where p+4 < 3p        [as p≥3]

3p < 4p-1          [as p≥3]

⇒  4p-1> 3p > p+4

⇒AB>BC>AC

Angle opposite to AB ,BC and AC is m∠C ,m∠A and m∠B.

Therefore mC > mB > mA    [∵Angle opposite to greater side is greater]

Thus , mC > mA > mB is correct regarding the angles of the  triangle ABC.

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1