The length of a rectangle is twice its width. the perimeter is 60 ft. find its area.

200 feet squared

Step-by-step explanation:

W=Width

2W=Length

Perimeter = 2*Length + 2*Width

Now use substitution for the Length

60 = 2(2W) + 2(W)

60=4W + 2W = 6W divide both sides by 6

60/6 = 6W/6

10 = W

Width = 10 and Length is twice as long so it is 20. 10+10+20+20=60

The area is Length * Width = 20*10=200

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !