For an object whose velocity in ft/sec is given by v(t) = −t^2 + 4, what is its displacement, in feet, on the interval t = 0 to t = 3 secs? 7.67 −3.00 −0.33 3.00

The answer is 3 feet

Step-by-step explanation:

The displacement  function is the integration of the velocity formula, so:

if we evaluate the displacement for the upper and lower limit it would be

D = total displacement = d(3) - d(0)

step-by-step explanation:

c. 4 1/4 pounds