What is the area of a parallelogram whose vertices are a(−12, 2) , b(6, 2) , c(−2, −3) , and d(−20, −3) ? enter your answer in the box.

To solve this, we simply have to get the length and the width. Based from the graph, we can see that the length is connected by 2 points (-12, 2) and (6, 2) or (-20, -3) and (-2, -3). The height between the two lengths is 5 which can be counted manually.

We use the distance formula to calculate the length from either pair of points.

length^2 = [(-12 – 6)^2 + (2 – 2)^2]

length = 18

Therefore the area is:

Area = length * height

Area = 18 * 5

Area = 90

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: