In △abc , the coordinates of vertices a and b are a(1,2), and b(−3,−1)? for each of the given coordinates of vertex c, is △abc a right triangle?

ABC would be right angle triangle if C(1,-1) or C(-3,2)

Step-by-step explanation:

In △ABC , the coordinates of vertices A and B are A(1,2), and B(−3,−1)

We need to find the third vertex of triangle ABC.

ABC is a right angle triangle.

A(1,2) and B(-3,-1)

Using A and B, Two possible right angle triangle.

Case 1: If we draw a vertical line at A and horizontal line at B then intersection point of vertical and horizontal would be third vertex of triangle ABC.

Vertical line at A, x=1

Horizontal line at B, y=-1

Vertex C: (1,-1)

Case 2: If we draw a horizontal line at A and vertical line at B then intersection point of vertical and horizontal would be third vertex of triangle ABC.

Vertical line at B, x=-3

Horizontal line at C, y=2

Vertex C: (-3,2)

Thus, ABC would be right angle triangle if C(1,-1) or C(-3,2)

Please see the attachment to see the process graphically.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%