That is the polynomial in x^3+6x^2+5x-12?

X³ + 6x² + 5x - 12

= x³ - x² + 7x² + 12x - 12

If we add all the coefficients, we get that the answer is 0. Thus, (x-1) is a factor of polynomial.

= x²(x-1) + 7x(x-1) + 12(x-1)

on re-arranging (x-1) as a common factor ;

= (x-1)(x²+7x+12) (1)

Now, we factorize (x² + 7x + 12)

(x² + 7x + 12)

= x² + 3x + 4x + 12
= x(x + 3) + 4(x + 3)

= (x + 4)( x +3)  (2)

On substituting for p(x) in 1 and 2, we get

(px) = (x-1)(x+4)(x+3)