What is the value of b2 - 4ac for the following equation? 2x2 + 3x = -1

First, we will rearrange the equation to be in the form of:
ax^2 + bx + c = 0
Doing this, the equation will become:
2x^2 + 3x + 1 = 0
Then,
a is the coefficient of x^2, therefore, a = 2
b is the coefficient of x, therefore, b = 3
c is the coefficient in the term that has no x (x^0), therefore, c = 1

Then, we will substitute in the equation to get the desired value:
b^2 - 4ac = (3)^2 - 4(2)(1) = 9 - 8 = 1