Which of the following describes how to graph the line whose equation is y = 2/3 x - 1? a. plot the point (0, -1), move up 3 and right 2, plot the point, and draw the line through these 2 points. b. plot the point (0, -1), move up 2 and right 3, plot the point, and draw the line through these 2 points. c. plot the point (-1, 0), move up 2 and right 3, plot the point, and draw the line through these 2 points.

Option: B is the correct answer.

  B. Plot the point (0, -1), move up 2 and right 3, plot the point, and draw the line through these 2 points.

The equation of a line is given by:

A)

Plot the point (0, -1), move up 3 and right 2, plot the point, and draw the line through these 2 points.

Now when we move up 3 units and 2 units to the right then the point is: (2,2)

This means that the graph of the function must pass through (2,2)

when x=2 then the value from the actual function is:

Hence, option: A is incorrect.

C)

Plot the point (-1, 0), move up 2 and right 3, plot the point, and draw the line through these 2 points.

This means that the equation of the line must pass through (-1,0) and (2,2)

Now when x= -1 we have:

Hence, option: C is incorrect.

B)

Plot the point (0, -1), move up 2 and right 3, plot the point, and draw the line through these 2 points.

i.e. the line must pass through (0,-1) and (3,1)

Now we find the equation of a line using the two points as:

where (a,b) and (c,d) are the passing through points.

Here (a,b)=(0,-1) and (c,d)=(3,1)

Hence, we have the equation of line as:

Hence, it matches the actual equation of the line.

Hence, option: B is the correct answer.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

true

step-by-step explanation: