Find the probability that when 200 reservations are accepted for united flight 15, there are more passengers than seats available

The solution for this problem is:

We know the problem has the following given:

Sample size of 200

X = 182

And the probability of .9005; computation: 1 - .0995 = .9005

So in order to get the probability:

P (x >= 182) = 1 – 0.707134 = .292866 is the probability that when 200 reservations 
are recognized, there are more passengers showing up than there 
are seats vacant.

The other solution is:

p (>= 182) = p(183) + P(184) + P(185) + ... + P(199) + P(200) = 0.292866

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.