Beth is taking a nine-question multiple-choice test for which each question has three answer choices, only one of which is correct. beth decides on answers by rolling a fair die and marking the first answer choice if the die shows 1 or 2, the second if the die shows 3 or 4, and the third if the die shows 5 or 6. find the probability of the stated event.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

5/20 so 25%

step-by-step explanation: