Complete the coordinate proof of the theorem. given: a b c d is a parallelogram. prove: the diagonals of a b c d bisect each other. enter your answers in the boxes. the coordinates of parallelogram abcd are a(0, 0) , b(a, 0) , c( , ), and d(c, b) . the coordinates of the midpoint of ac¯¯¯¯¯ are ( , b2 ). the coordinates of the midpoint of bd¯¯¯¯¯ are ( a+c2 , ). the midpoints of the diagonals have the same coordinates. therefore, ac¯¯¯¯¯ and bd¯¯¯¯¯ bisect each other.

The coordinates of parallelogram ABCD are A(0, 0) , B(a, 0) , C(a+c, b), and D(c, b)

The coordinates of the midpoint of AC are ((a+c)/2, b/2)

The coordinates of the midpoint of BD are ((a+c)/2, b/2)

Step-by-step explanation:

The x-coordinate of C is the addition of x-coordinates of D and B

The y-coordinate of C is the same as y-coordinates of D

The x-coordinate of the midpoint of AC are half of the distance in x-coordinate between A and C, that is, (a+c)/2

The y-coordinate of the midpoint of DB are half of the distance in y-coordinate between D and B, that is, b/2

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2