Three zeroes in a fifth degree polynomial function are 1/3,4-61,and -2+11i what are the remaining zeroes of the function? 4+6i,-2-11i -1/3,4+6i,2+11i -4+6i,2-11i 3, 4+6i,-2-11i

The degree of the polynomial is 5, therefore are 5 zeros (real or imaginary).
The given zeros are
1/3, 4 - 6i, and  -2 + 11i.

Because complex zeros always occur as conjugate pairs, the remaining complex zeros are
4 + 6i and -2 - 11i.

4 + 6i, -2 - 11i.