Mathematics, 19.07.2019 13:00 stricklandashley43
What is the equation for a line that passes through (-7, 2) and is perpendicular to the graph of y=-1/2x+3
Answers: 2
![\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -7}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 2 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=2[x-(-7)] \\\\\\ y-2=2(x+7)\implies y-2=2x+14\implies y=2x+16](/tpl/images/0107/8931/353fc.png)
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