Amodel jet is fired up in the air from a 20-foot platform with an initial upward velocity of 68 feet per second. the height of the jet above ground after t seconds is given by the equation h=-16t^2+68t+20, where h is the height of the jet in feet and t is the time in seconds since it is launched. what is the maximum height the jet reaches, to the nearest foot? a. 92 feet b. 20 feet c. 68 feet d. 16 feet

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

363 square inches

step-by-step explanation:

surface area of a pyramid is b + 1/2ph

b is the area of the base: 11 x 11 = 121

p is the perimeter of the base: 11 + 11 + 11 + 11 = 44

h is the height of the pyramid: 11

121 + 1/2(44)(11)

121 + 242

363