Mathematics, 20.07.2019 01:10 ryansingl19
The function f(x)=18000(0.52)x represents the value in dollars of a vehicle x years after it has been purchased new. what is the average rate of change in value per year between years 4 and 8? −$18000/year −$1219.87/year −$304.97/year −$0.52/year
Answers: 2
![\frac{f(8)-f(4)}{8-4}\\\\=\frac{18000(0.52)^8-18000(0.52)^4}{4}\\\\=\frac{18000[(0.52)^8-(0.52)^4]}{4}\\\\=\frac{18000[0.00534-0.07311]}{4}\\\\=\frac{18000\times-0.06777}{4}\\\\=\frac{-1219.86}{4}=-304.97](/tpl/images/0109/8737/8a975.png)
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