Q: a: anna is drawing the midsegment of δ lnm that is parallel to ln. what are the coordinates of the endpoints of the midsegment? a) (3, 4) and (3, 7) b) (4, 4) and (4, 7) c) (2, 7) and (2, 3.5) d) (4, 7) and (4, 3.5)

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: