The length of a rectangle is four times the width. the perimeter of the rectangle is 45 inches. write a system of equations that represents this problem. what is the area of the rectangle?

Hello there,w= 1ul= 4uperimeter = l + l + w + w45 inches= 4u + 4u + 1u + 1u  10u = 45 inches1u = 45 inches/ 10      = 4.5 incharea= l x warea= 4.5 inch x (4.5 x 4)          = 4.5 inch x 18 inch        = 81 square inch  hope this : ))~top

The i'm not so sure though. this question could use a little more explanatory reasoning.

In the first triangle 80+20+p=180 (since sum of all angles of a triangle is 180)so p= 80also in second triangle 55+45+q=180 (since sum of all angles of a triangle is 180)so q=80so we can conclude that p=80 degrees q=80 degrees so p=q=80 degreeshence option b is correct