In developing an interval estimate for a population mean, a sample of 50 observations was used. the interval estimate was 19.76 â± 1.32. had the sample size been 200 instead of 50, the interval estimate would have been:

The formula for interval estimate would be: μ = M ± Z(sM)

Where: μ is estimate

M is the mean 

Z is the z value

(sM) is the standard error

μ = M ± Z(sM)

n = 200 rather than 50 (√200 = 2√50)

⇒ ME = (1/2) * 1.32 = .66

Using the formula above, plugging this in will give us: μ = 19.76 ± .66

 = 19.76  ±  .66 is the confidence interval or interval estimate

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98