David and joseph have a total of 328 marbles. matthew and david have 176 marbles. joseph has 5 times as many marbles as matthew. how many marbles does david have?

D:  count of David's marbles
j:  count of Joe's marbles
m:  count of Matt's marbles

Then d + j = 328         => d + 5m = 328
and    m+d = 176   =>     -d  - m   = -176
and     j = 5m                    These two equations combine to produce
                                              4m = 152.  Thus, m = 152/4 = 38.

If m = 38, then j = 5(38) = 190.  Thus, d = 328 - j, or 328 - 190, or 138.

Dave has 138 marbles, Matthew has 38, and Joe has 190. 

  d + j     = 328
-(d + m  = 176)

    j -m = 152.  But m = j/5, so j - j/5 = 152.  Then 4j/5 = 152, or
    
     (5/4)(4j/5) = (5/4)(152) = 190.  j = 190.  Since d + j = 328, d = 138.

David has 138 marbles.  Joe has 5 times as Matt or 120.  m has 96 marbles.

There are two bc a studen that equals to 2

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!