12. the table shows the height of a plant as it grows. which equation in point-slope form gives the plant's height at any time (1 point) time (months) | plant height (cm) 2 | 16 4 | 32 6 | 48 8 | 64 (a). y - 16 = 8(x - 2) (b). y - 16 = 8x - 2 (c). y + 16 = 8(x + 2) (d). the relationship is nonlinear 14. write y = (-5/8)x + 3 in standard form using integers (1 point) (a). 5x + 8y = -24 (b). 5x + 8y = 24 (c). 5x - 8y = 24 (d). -5x + 8y = 24 15. write an equation for the line that is parallel to the given line and passes through the given point (1 point) y = 3x + 7; (2, 10) (a). y = 3x + 11 (b). y = 3x + 4 (c). y = -3x + 4 (d). y = (-1/3)x + 4 16. tell whether the lines for each pair of equations are parallel, perpendicular, or neither (1 point) y = -2x + 4 -5x + 10y = 5 (a). parallel (b). perpendicular (c). neither 17. tell whether the lines for each pair of equations are parallel, perpendicular, or neither (1 point) y = -1/4x + 10 -2x + 8y = 6 (a). parallel (b). perpendicular (c). neither 18. write the equation of a line that is perpendicular to the given line and that passes through the given point (1 point) y - 4 = 5/2 (x + 3); (-7, 8) (a). y - 8 = -2/5 (x - 7) (b). y - 8 = 2/5 (x - 7) (c). y - 8 = -2/5 (x + 7) (d). y - 8 = 2/5 (x + 7)

Ques 12)

Time (months) | Plant Height (cm)

              2 | 16

              4 | 32

              6 | 48

              8 | 64

Now, we see that the line will pass through (2,16) and (4,32)

Now, the equation of line passing through (a,b) and (c,d) is given by:

Here (a,b)=(2,16) and (c,d)=(4,32)

Hence, the equation of line is:

The relationship is clearly linear since we can relate them as:

y=8x

Hence, option: A is correct:

(A). y - 16 = 8(x - 2)

Ques 14)

y = (-5/8)x + 3

In standard form it is:

Hence, option: B is correct.

Ques 15)

y = 3x + 7; (2, 10)

As the line is parallel hence the slope must be same. (i.e. slope of the line y=mx+c is m.

So, here slope=3)

Now,

The line also passes through (2,10).

Hence, the equation is:

y=3x+4

( since, when x=2

y=3×2+4=6+4=10)

Ques 16)

y = -2x + 4 -------------(1)

-5x + 10y = 5-------------(2)

On solving second equation we have:

slope of first line (m)= -2

slope of second line (m')= 1/2

As m.m'=-1

Hence, the lines are perpendicular.

Ques 17)

y = -1/4x + 10 ---------(1)

-2x + 8y = 6-------(2)

On converting equation (2) we have:

As slope of first line is(m): -1/4

and that of second line is(m'): 1/4

Now,

then the lines are perpendicular.

and if m=m' then lines are parallel.

Hence, here the answer is neither.

Ques 18)

y - 4 = 5/2 (x + 3); (-7, 8)

slope of this line is: 5/2

As the line is perpendicular hence it's slope will be: -2/5

Also it passes through (-7,8) hence, the equation is:

(C). y - 8 = -2/5 (x + 7)

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

answer:

125 yards

explanation:

75+50=125. that is my answer