At what point does the terminal side of the angle 5π/6 in standard position intersect the unit circle?

The angle of 5π/6 is 150 degree. start from the positive side of the x axis, rotate counterclockwise for 150 degree, the terminal side is in the second quadrant, forming a 30 degree angle with the negative side of the x axis. This 30 degree angle is what we need to focus on. 
Draw a vertical line from your terminal point straight down to the negative side of the x axis, and draw another line from the terminal point to the center of the unit circle. Now you have a right triangle.
In a unit circle, the radius, that is, the hypotenuse of of this right triangle, is always 1.
sin30=y:r =1/2, so y is 1/2
cos30=x:r=√3/2, so x is √3/2
because the terminal point is in the second quadrant, x is negative, y is positive, therefore, the standard position of the intersection is at (-√3/2, 1/2)

Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.