(-6,-10) , y axis. (-11,3),x axis. (8,2) ,x axis

The point (4,3) reflected about the x axis,=> The x remains the same, the y flips over the x axis to be negative      (4,3) ==>> (4,-3) The point (-3,-8) is reflected in the y-axis.=> The y remains the same, the x flips over the y axis to be negative
      (-3,-8)==>>(3,-8) The point (2,4) is reflected in the line x = -3.=> The x remains the same, the y flips over the x= -3 line.      Instead of reflecting over the x axis (or the x = 0) line      and just being +4 or 4 above the x axis to -4 or 4 below the x axis      you have +4 being 7 above the x= -3 line so you need      7 below the x= -3 line or -10  SO       (2,4)==>>(2,-10) The point (a, b) is reflected in the line y = x      Consider that the line x=y is a 45 degree diagonal.      Imagine a point on the x axis at +3  i.e. (3,0)      Imagine a line perpendicular to x=y from the point (3,0)            (sorry there is no way to draw on here - try drawing it)     The line would hit the y axis at (0,3)     So you can see the x becomes y and y becomes x.      (a,b)==>>(b,a) ForΔXYZ is defined by its vertices X(1,3), Y(-3,5), and Z(0, -5).        ΔXYZ is reflected in the y-axis.So for each of of the 3 points X, Y, and Z reflect them about        the y axis the same way in the second example above        and you will have the 3 new points X’,  Y', and Z’ The translation T: (x, y) → (x -2, y + 4) maps the point (2, -3) to
The translation T: (x, y) → (x + 3, y - 2) maps the point (-4, -3) to      What you need to do here is just plug the values for X and Y into the translation.      e.g. for T: (x, y) → (x -2, y + 4)  plug (2,-3) of x=2 y=-3 into (x -2, y + 4) and get the new values.

Yes you do, so £1973.09 - £1473.50 = £499.59 so tim overpaid £499.59 .hope this ; )