Agroup consists of 6 men and 5 women. five people are selected to attend a conference. in how many ways can 5 people be selected from this group of 11? in how many ways can 5 men be selected from the 6 men? find the probability that the selected group will consist of all men.

To compute for combinations, we will use the method nCr = n! / r! * (n - r)!

Where: n signifies the number of items, and r signifies the number of items being selected at a time.

Solution

1.       11C5 = 11!/ 5! * (11-5)! = 462 ways

2.       6C5 = 6!/ 5! * (6-5)! = 6 ways

3.       6/462 = 1/77 or 0.1230 is the probability that the selected group will consist of all men.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

it's