What are the coordinates of the endpoints of the midsegment for △rst that is parallel ts¯¯¯¯¯ ?

The end points of midsegement for triangle RST are (1,3) and(4,3) which is parallel to TS.

Step-by-step explanation:

We are given that a figure of  triangle RTS in which the coordinates of R(0,6) , T(2,0) and S(8,0).

We have to find the end points of midsegment for triangle RST that is parallel TS

Let AB is midsegment where A is the mid point of segment RT and B is the midpoint of segment RS of triangle RST which is parallel to the segment TS.

To find the coordinates of end point of midsegment AB using midpoint formula

Midpoint formula :

The coordinate of A

,

The coordinates of A is (1,3).

The coordinates of mid point B

The coordinates of midpoint B is (4,3).

Therefore, the end points of midsegement for triangle RST are (1,3) and(4,3) which is parallel.

theres no picture: /

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.