What point in the feasible region maximizes p for the objective function p = 2x + 3y? constraints 2x+y≤15 x+3y≤20 x≥0, y≥0 a. (0, 15) b. (5, 5) c. (8, 7) d. (2, 6)

Suppose 2x + y = 15 eq 1 . x + 3y = 20 eq 2. Multiplying eq (1) by 1 and (2) by 2 and subtracting the result We have: 2x + y = 15 and 2x +6y =40.If we subtract, we have y - 6y = 15 - 40. So we have -5y = -25. y is 5. Substiting into eq (1), we have 2x + 5 = 15. 2x = 15-5 =10 Hence X =5.Hence option B is the correct option.

The answer is $9.90 with rounding to the nearest tenth