Find the equation of the line that is perpendicular to the given line and passes through the given point. enter the right side of the equation as a single fraction. y = 5x − 1 2 ; (3, 3)

Y = 5x - 12the slope here is 5. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, u flip the slope and change the sign. So we have 5 or 5/1flip the slope making it 1/5change the sign making it -1/5. So the perpendicular line will have a slope of -1/5.

y = mx + b
slope(m) = -1/5
(3,3)x = 3 and y = 3
now we sub into the formula and find b, the y int
3 = -1/5(3) + b
3 = -3/5 + b
3 + 3/5 = b
15/5 + 3/5 = b
18/5 = b

so ur equation is : y = -1/5x + 18/5

Ithink the answer would be knew