What is the y-intercept of the following equation. 3x-2y=6

3x-2y=6

1) Add -3x to both sides.
  3x−2y=6
+3x      +3x
-----------------
−2y=−3x+6

2) Divide both sides by -2.
= 

y=32x−3

3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6

4) Combine like terms
3x-64x+6=6
-61x+6=6

5) Subtract 6 from each side of the equation
-61x+6=6
        -6 -6        (+6-5 gets crossed out)
--------------
-61x=0

6) Divide both sides by -61
 
x=0

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Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3

y=32(0)-3
y=0-3
y=-3

(0,-3)