Write the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2x + y = -5. include your work in your final answer. type your answer in the box provided or use the upload option to submit your solution.

y = -2x + 2

Step-by-step explanation:

line, let's call it line r: has a y-intercept of 2 ⇒ x = 0 ⇒ (0,2) ∈ r

r is parallel to 2x + y = -5 ⇒ they have the same slope.

To find the slope, we have to isolate y ans see the x value:

2x + y = -5

y = -2x - 5

slope (m) = -2

To find r, we use y - y₀ = m(x - x₀), where (x₀,y₀) is any point that ∈ r. In our case (x₀,y₀) = (0,2) and m = -2

y - y₀ = m(x - x₀)

y - 2 = -2(x - 0)

y - 2 = -2x

y = -2x + 2

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.