What are the zeros of the function? what are their multiplicities? y=(x-2)(x+7)^3

1)2) x=2, multiplicity 1 x=-7, multiplicity is 3.

Step-by-step explanation:

1) The zeros of this function are the roots of it. Which number added to -2 will return 0 for the first factor (x-2)? Similarly, which one added to -7 for the second factor (x+7)³ will return 0?

2) The multiplicity of a function is the number of repeated times, a factor  of a polynomial function appears in its factored form. So,

The factor is (x+7) whose multiplicity is 3, then x=-7, multiplicity=3

The factor (x-2), then x=2, multiplicity =1

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

(23*2)-12=x     x=34

step-by-step explanation: