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![\bf \begin{cases} f(x)=6x\\ g(x)=4x+1\\ (f\circ g)(x)=f(~~g(x)~~) \end{cases} \\\\\\ f(~~g(x)~~)=6[g(x)]\implies f(~~g(x)~~)=6[4x+1] \\\\\\ f(~~g(x)~~)=24x+6](/tpl/images/0125/8550/94511.png)
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If f(x)=6x and g(x)=4x+1, find (f o g)(x)...
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