Ineed to solve this expression so there are no negative exponents or parentheses remaining.

The answer to this problem is (s∧11u²) because the s in both the parenthesis would be added together, even though the t in the first parenthesis looked like it was connected to the u when It looks like that that means that there is an imaginary positive one there so the t would cancel out which just leaves u. that is why our solution is (s∧11u²)

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3