An expression is shown below: f(x) = 5x2 + 2x − 3 part a: what are the x-intercepts of the graph of f(x)? show your work. (2 points) part b: is the vertex of the graph of f(x) going to be a maximum or minimum? what are the coordinates of the vertex? justify your answers and show your work. (3 points) part c: what are the steps you would use to graph f(x)? justify that you can use the answers obtained in part a and part b to draw the graph. (5 points)

Part a: the x intercepts are the zeros: 5x²+2x-3=0(5x-3)(x+1)=0x=3/5 or x=-1part b: the vertex is a minimum because the coefficient of x² is 5, a positive number.  the vertex is when x=-b/2a. in this case, b=2, a=5, so x=-2/10=-1/5; when x=-1/5, f(x)=5(-1/5)²+2(-1/5)-3=-16/5so the vertex is at (-1/5, -16/5)  part 3: locate the vertex, locate the zeros, try another two x values, for example x=0, f(x)=-3, x=1, f(x)=4. connect the 5 points to make the parabola. double check my calculation