Rectangle j'k'l'm' shown on the grid is the image of rectangle jklm after transformation. the same transformation will be applied on trapezoid stuv, as shown below: rectangle jklm is drawn on the grid with vertices j at negative 5, 1. k is at negative 5, 6. l is at negative 7, 6. m is at negative 7, 1. rectangle j prime k prime l prime m prime is drawn with vertices at j prime 4, 4. k prime is at 4, 9. l prime is at 2, 9. m prime is at 2, 4. trapezoid stuv is drawn with vertices at s is at 9, negative 6. t is at 9, negative 2. u is at 7, negative 2. v is at 6, negative 5. what will be the location of u' in the image trapezoid s't'u'v'? (16, −2) (14, −2) (14, 1) (16, 1)

Location U' in the image trapezoid will be (16, 1)

Step-by-step explanation:

Rectangle JKLM has been transformed to J'K'L'M'. So changed vertices of JKLM will become as

J(-5,1) → J'(4, 4)

K(5, 6) → K'(4, 9)

L(-7, 6) → L'(2, 9)) Transformation done was shifting of L to L' by (9, 3) [2-(-7)=9, 9-6=3]

M(-7, 1) → M'(2, 4)

Now we have find the find the transformed vertex U' by using the same transformation rule done in L → L'

Since coordinates of U are (7, -2), we will transform is to get get U'

x coordinates = 7 + 9 = 16

y coordinates = -2 + 3 = 1

So U' will be (16, 1).

x^5/3y^1/3 the correct answer

hope it

256π units²   (answer b)

step-by-step explanation:

the formula for the surface area of a sphere of radius r

is             a = 4πr²

and so, if r = 8 units, then the surface area is:

a = 4π(8 units)² = 256π units²   (answer b)